Newton's Method

To solve

(1)
$${e}^{x}-x=2$$

Write a function

(2)
$$f(x)={e}^{x}-x-2$$

Guess ${x}_{1}$, any constant you like

(3)
\begin{align} {x}_{2}={x}_{1}-\frac{f({x}_{1})}{f'({x}_{1})} \end{align}
(4)
\begin{align} {x}_{3}={x}_{2}-\frac{f({x}_{2})}{f'({x}_{2})} \end{align}

The solution x will get closer and closer to the really value.

page revision: 0, last edited: 09 May 2009 21:06